Questions & Answers

Question

Answers

\[39,52,106,359,628,3458,9502,7000\]

Answer

Verified

91.5k+ views

We can solve this question with three simple steps, which are given below:

Step 1: \[39\] is a two-digit number where digits \[9\] on unit place and \[3\] on tens place. So, it can be written in generalised form i.e., \[39 = 10 \times 3 + 9\].

Similarly, \[52\] is two-digit number, so it can be written in generalised form i.e. \[52 = 10 \times 5 + 2\]

Step 2: \[106\] is a three-digit number. So, it can be written in generalised form i.e.\[106 = 100 \times 1 + 10 \times 0 + 6\].

\[359\] is a three-digit number. So, it can be written in generalised form i.e., \[359 = 100 \times 3 + 10 \times 5 + 9\]

\[628\] is a three-digit number. So, it can be written in generalised form i.e., \[628 = 100 \times 6 + 10 \times 2 + 8\]

Step 3: \[3458\] is a four-digit number. So, \[3458 = 1000 \times 3 + 100 \times 4 + 10 \times 5 + 8\] is a generalised form.

Similarly, \[9502 = 1000 \times 9 + 100 \times 5 + 10 \times 0 + 2\]

and \[7000 = 1000 \times 7 + 100 \times 0 + 10 \times 0 + 0\] is a generalised form.

Similarly, a three-digit number can be written as \[100a + 10b + c\] in generalised form where \[a\] be any number from \[1\] to \[9\] while \[b\] and \[c\] be any number from \[0\] to \[9\].